Answer
$y' = -csc(e^x)cot(e^x) \times e^x$
Work Step by Step
$y = csc (e^x)$
$y' = (csc (e^x))'$
The inner function is $g(x) = e^x$
and the outer function is $f(u) = csc(u)$
$f'(u) = -csc (u) cot ( u)$
$y' = (csc(e^x))' = -csc(g(x))cot(g(x)) g'(x)= -csc(e^x)cot(e^x) \times e^x$
