Answer
$y' = sec^2(e^x)\times e^x$
Work Step by Step
$y = tan(e^x)$
$y' = (tan(e^x))'$
The inner function is $g(x) = e^x$
and the outer function is $f(u) = tan(u)$
$f'(u) = sec^2(u)$
$y' = (tan(e^x))' = sec^2(g(x)) g'(x)= sec^2(e^x)\times e^x$
