Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 15 - Multiple Integrals - 15.1 Double Integrals over Rectangles - 15.1 Exercises - Page 1039: 9

Answer

$24 \sqrt 2$

Work Step by Step

$\int_{-1}^5 \int_2^6 \sqrt 2 dxdy = \int_{-1}^5 \sqrt 2 x \big|_2^6 dy$ =$\int_{-1}^5 \sqrt 2 (6-2) dy$ =$\int_{-1}^5 4 \sqrt 2 dy$ =$4 \sqrt 2 y\big|_{-1}^5$ =$4 \sqrt 2 [5-(-1)]$ = $4 \sqrt 2 (6)$ =$24 \sqrt 2$
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