Answer
$3$
Work Step by Step
$\int \int_R (4-2y) dA = \int_0^1 \int_0^1 (4-2y) dydx$
$= \int_0^1 (4y-y^2)\big|_0^1 dx$
$= \int_0^1 (3-0) dx$
$= 3x\big|_0^1$
$= 3(1-0)$
$= 3$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 15 - Multiple Integrals - 15.1 Double Integrals over Rectangles - 15.1 Exercises - Page 1039: 11
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