Answer
222
Work Step by Step
$ = \int_1^4 \int_0^2 (6x^2 y – 2x) dy dx$
$= \int_1^4 (3x^2 y^2 – 2xy)\big|_0^2 dx$
$= \int_1^4 (12x^2 – 4x) dx$
$= (4x^3 – 2x^2)\big|_1^4$
$= [(256-32) – (4-2)]$
$= 224-2$
$= 222$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 15 - Multiple Integrals - 15.1 Double Integrals over Rectangles - 15.1 Exercises - Page 1039: 15
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