Answer
$24$
Work Step by Step
$ \int_R (2x+1)dA = \int_0^4 \int_0^2 (2x+1)dxdy$
$= \int_0^4 (x^2+x)\big|_0^2 dy$
$= \int_0^4 (6-0) dy$
$= 6y\big|_0^4$
$= 6(4-0)$
$=24$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 15 - Multiple Integrals - 15.1 Double Integrals over Rectangles - 15.1 Exercises - Page 1039: 10
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