Answer
$\frac{x^{2}}{2}-3x+11\ln|x+3|+C$
Work Step by Step
long division gives us
$\frac{x^{2}+2}{x+3}$ = $x-3+\frac{11}{x+3}$
so
$\int{\frac{x^{2}+2}{x+3}}dx$ = $\int({x-3+\frac{11}{x+3}})dx$ = $\frac{x^{2}}{2}-3x+11\ln|x+3|+C$
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