Answer
$$ x-\ln |x+4|+C$$
Work Step by Step
Given $$\int \frac{(x+3) d x}{x+4}$$
Since
\begin{align*}
\int \frac{(x+3) d x}{x+4}&=\int \frac{[(x+4) -1]d x}{x+4}\\
&=\int\left(1- \frac{1}{x+4}\right)dx\\
&= x-\ln |x+4|+C
\end{align*}
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 8 - Techniques of Integration - 8.5 The Method of Partial Fractions - Exercises - Page 423: 10
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
