Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 6 - Applications of the Integral - Chapter Review Exercises - Page 320: 46

Answer

$\frac{\pi}{6}$

Work Step by Step

$V$ = ${\pi}\int_0^{\frac{1}{a}}a^{2}(x-ax^{2})dx$ $V$ = ${\pi}(\frac{1}{2}a^{2}x^{2}-\frac{1}{3}a^{3}x^{3})|_0^{\frac{1}{a}}$ $V$ = $\frac{\pi}{6}$
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