Answer
$-4{\pi}(1-e^{-\frac{1}{2}})$
Work Step by Step
$V$ = $2{\pi}\int_0^{1}2xe^{-\frac{x^{2}}{2}}dx$
$V$ = $-4{\pi}e^{-\frac{x^{2}}{2}}|_0^{1}$
$V$ = $-4{\pi}(1-e^{-\frac{1}{2}})$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 6 - Applications of the Integral - Chapter Review Exercises - Page 320: 39
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