Answer
$24\pi({\sqrt 3}-1)$
Work Step by Step
$V$ = ${\pi}\int_1^{3}[(3+\frac{1}{\sqrt x})^{2}-(3-\frac{1}{\sqrt x})^{2}]dx$
$V$ = ${12\pi}\int_1^{3}x^{-\frac{1}{2}}dx$
$V$ = $24\pi{\sqrt x}|_1^{3}$
$V$ = $24\pi({\sqrt 3}-1)$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 6 - Applications of the Integral - Chapter Review Exercises - Page 320: 38
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