Answer
$\frac{\pi}{6}m^{4}$
Work Step by Step
$V$ = ${\pi}\int_{0}^{m^{2}}[(\sqrt y)^{2}-(\frac{y}{m})^{2}]dy$
$V$ = $\pi(\frac{1}{2}y^{2}-\frac{y^{3}}{3m^{2}})|_0^{m^{2}}$
$V$ = $\frac{\pi}{6}m^{4}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 6 - Applications of the Integral - Chapter Review Exercises - Page 319: 27
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