Answer
$$27$$
Work Step by Step
Since the average value of $g(t)$ is given by
\begin{align*}
M&=\frac{1}{5-2} \int_{2}^{5} g(t) d t\\
9&=\frac{1}{3} \int_{2}^{5} g(t) d t
\end{align*}
Then, we have:
$$ \int_{2}^{5} g(t) d t=27$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 6 - Applications of the Integral - Chapter Review Exercises - Page 319: 25
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