Answer
$2.7552 \ kg$
Work Step by Step
The total mass $(M)$ of the rod can be calculated as:
$Mass, M= \int_{0}^{1.2} (1+2x+\dfrac{2x^3}{9}) \ dx \\=[x+x^2+\dfrac{x^4}{18}]_0^{1.2} \\=1.2+(1.2)^2+\dfrac{(1.2)^4}{18} \approx 2.7552 \ kg$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 6 - Applications of the Integral - Chapter Review Exercises - Page 319: 17
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
