Answer
$V$ = $36\sqrt 3$
Work Step by Step
width = $2\sqrt y$
height= $y^{3}$
$V$ = $2\int_0^{3}y^{\frac{7}{2}}dy$
$V$ = $\frac{4}{9}y^{\frac{9}{2}}|_0^3$
$V$ = $36\sqrt 3$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 6 - Applications of the Integral - 6.2 Setting Up Integrals: Volume, Density, Average Value - Exercises - Page 296: 14
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