Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 6 - Applications of the Integral - 6.2 Setting Up Integrals: Volume, Density, Average Value - Exercises - Page 296: 13

Answer

$V$ = $18$

Work Step by Step

$V$ = $\int_0^3(2\sqrt y)(2\sqrt y)dy$ $V$ = $\int_0^{3}4ydy$ $V$ = $2y^{2}|_0^3$ $V$ = $18$
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