Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 6 - Applications of the Integral - 6.2 Setting Up Integrals: Volume, Density, Average Value - Exercises - Page 296: 12

Answer

$V$ = $\frac{1}{3}l^{4}$

Work Step by Step

$V$ = $\int_0^l(lx^{2})dx$ = $(\frac{1}{3}lx^{3})|_0^l$ = $\frac{1}{3}l^{4}$
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