Answer
$V$ = $\frac{\pi}{24}$
Work Step by Step
$V$ = $\int_{0}^{1}\frac{\pi}{8}(1-y)^{2}dy$
$V$ = $\frac{\pi}{8}(1-2y+y^{2})|_{0}^1$
$V$ = $\frac{\pi}{8}(y-y^{2}+\frac{1}{3}y^{3}|_0^1$
$V$ = $\frac{\pi}{24}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 6 - Applications of the Integral - 6.2 Setting Up Integrals: Volume, Density, Average Value - Exercises - Page 296: 10
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