Answer
$27t^{1/3}+\frac{6}{5}t^{10/3}+c.$
Work Step by Step
We have $$\int (9t^{-2/3}+4t^{7/3})dt =\frac{9}{1/3}t^{1/3}+\frac{4}{10/3}t^{10/3}+c=27t^{1/3}+\frac{6}{5}t^{10/3}+c.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - Chapter Review Exercises - Page 278: 22
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