Answer
$$\int(4x^3-2x^2)dx= x^4-\frac{2}{3}x^3+c $$
Work Step by Step
We have
$$\int(4x^3-2x^2)dx=\frac{4}{4}x^4-\frac{2}{3}x^3+c= x^4-\frac{2}{3}x^3+c.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - Chapter Review Exercises - Page 278: 17
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