Answer
$$\int (4t^{-3}-12t^{-4})dt =-2t^{-2}+4t^{-3}+c.$$
Work Step by Step
We have
$$\int (4t^{-3}-12t^{-4})dt =-\frac{4}{2}t^{-2}+\frac{12}{3}t^{-3}+c=-2t^{-2}+4t^{-3}+c.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - Chapter Review Exercises - Page 278: 21
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