Answer
$f(x) $ has no critical points and $ f(x)$ is increasing for all $x$.
Work Step by Step
Given $$y=x^{5}+x^{3}+x$$
Since
$$f'(x) = 5x^4+3x^2+1 $$
Then for all $x$, we have $f'(x)\geq 1$. Hence, $f(x) $ has no critical points and $ f(x)$ is increasing for all $x$.