Answer
$\frac{(2x+1)y^{2}}{y^{2}-1}$
Work Step by Step
Differentiating implicitly with respect to $ x $, we have
$ y'+\frac{-y'}{y^{2}}=2x+1$
$\implies y'(1-\frac{1}{y^{2}})=2x+1$
$\implies y'=\frac{2x+1}{1-\frac{1}{y^{2}}}$
$\implies y'=\frac{(2x+1)y^{2}}{y^{2}-1}$
