Answer
$\frac{3x^{2}-y^{2}-2xy^{5}}{2xy+x^{2}5y^{4}}$
Work Step by Step
Differentiating with respect to $ x $, we have
$1\times y^{2}+2yy'\times x+2xy^{5}+x^{2}5y^{4}y'-3x^{2}=0$
$\implies 2xyy'+x^{2}5y^{4}y'=3x^{2}-y^{2}-2xy^{5}$
$\implies y'=\frac{3x^{2}-y^{2}-2xy^{5}}{2xy+x^{2}5y^{4}}$
