Answer
$-3x^{2}\sin(x^{3})$
Work Step by Step
Let $ g(x)=u= x^{3}$ and $ f(u)=y=\cos u $
Then, $ y=f(g(x))=\cos(x^{3})$
Using the chain rule, we have
$\frac{dy}{dx}=\frac{dy}{du}\times\frac{du}{dx}=-\sin (u)\times3x^{2}=-3x^{2}\sin(x^{3})$
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