Answer
$f'(g(x)) = 2cosx$
Work Step by Step
$f(u) = 2u + 1, g(x) = 2x+1$
$f(g(x)) = 2(sinx) + 1$
$f'(g(x)) = 2cosx + 0$
$f'(g(x)) = 2cosx$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - 3.7 The Chain Rule - Exercises - Page 146: 24
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