Answer
$\lim\limits_{t \to 3}\frac{h(t)}{t}=\lim\limits_{t \to 3}h(t)\times\lim\limits_{t \to 3}\frac{1}{t}=5$
Or $\lim\limits_{t \to 3}h(t)\times\frac{1}{\lim\limits_{t \to 3}t}=5$
$\implies \lim\limits_{t \to 3}h(t)\times\frac{1}{3}=5$
Which gives:
$\lim\limits_{t \to 3}h(t)=5\times3=15$
Work Step by Step
See the answer above.
