Answer
16
Work Step by Step
$\lim _{y\rightarrow \dfrac {1}{3}}\left( 18y^{2}-4\right) ^{4}=\left( 18\times \left( \dfrac {1}{3}\right) ^{2}-4\right) ^{9}=\left( 2-a\right) ^{4}=\left( -2\right) ^{4}=16$
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