Answer
$=\dfrac {1}{16}$
Work Step by Step
$\lim _{x\rightarrow -4}\dfrac {g\left( x\right) }{x^{2}}=\dfrac {\lim _{x\rightarrow -4}g\left( x\right) }{x^{2}}=\dfrac {1}{\left( -4\right) ^{2}}=\dfrac {1}{16}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 2 - Limits - 2.3 Basic Limit Laws - Exercises - Page 59: 29
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