Answer
$=\dfrac {1}{5}=0.2$
Work Step by Step
$\lim _{x\rightarrow -1}\dfrac {x}{x^{3}+4x}=\dfrac {-1}{\left( -1\right) ^{3}+4\times \left( -1\right) }=\dfrac {-1}{-1+\left( -a\right) }=\dfrac {-1}{-5}=\dfrac {1}{5}=0.2$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 2 - Limits - 2.3 Basic Limit Laws - Exercises - Page 59: 19
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