Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 15 - Differentiation in Several Variables - Chapter Review Exercises - Page 835: 38

Answer

The equation of the tangent plane at $P = \left( {0,3, - 1} \right)$ is $4x + y - 2z = 5$.

Work Step by Step

Write the surface: $F\left( {x,y,z} \right) = xy + y - z{{\rm{e}}^x} - {{\rm{e}}^{z + 1}} = 3$ The partial derivatives are ${F_x} = y - z{{\rm{e}}^x}$, ${\ \ \ }$ ${F_y} = x + 1$, ${\ \ \ }$ ${F_z} = - {{\rm{e}}^x} - {{\rm{e}}^{z + 1}}$ At $P = \left( {0,3, - 1} \right)$, ${F_x}\left( {0,3, - 1} \right) = 4$, ${\ \ \ }$ ${F_y}\left( {0,3, - 1} \right) = 1$, ${\ \ \ }$ ${F_z}\left( {0,3, - 1} \right) = - 2$ By Theorem 5 of Section 15.5, the tangent plane to the surface at $P = \left( {0,3, - 1} \right)$ has equation ${F_x}\left( {0,3, - 1} \right)\left( {x - 0} \right) + {F_y}\left( {0,3, - 1} \right)\left( {y - 3} \right) + {F_z}\left( {0,3, - 1} \right)\left( {z + 1} \right) = 0$ $4x + \left( {y - 3} \right) - 2\left( {z + 1} \right) = 0$ $4x + y - 2z = 5$ So, the equation of the tangent plane at $P = \left( {0,3, - 1} \right)$ is $4x + y - 2z = 5$.
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