Answer
$$
(\mathbf{i}-3 \mathbf{j}+2 \mathbf{k}) \times(\mathbf{j}-\mathbf{k})
=\mathbf{i}+\mathbf{j}+\mathbf{k}
$$
Work Step by Step
$$
(\mathbf{i}-3 \mathbf{j}+2 \mathbf{k}) \times(\mathbf{j}-\mathbf{k})\\=\mathbf{k}-(-\mathbf{j})-3(0-\mathbf{i})+2(-\mathbf{i}-0)\\
=\mathbf{i}+\mathbf{j}+\mathbf{k}
$$
