Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.2 Vectors in Three Dimensions - Exercises - Page 659: 33

Answer

$${\bf{r}}(t) = \langle 1+2t,2+t,-8+3t \rangle.$$

Work Step by Step

A vector parametrization for the given line is given by $${\bf{r}}(t)= \langle 1,2,-8 \rangle +t \langle 2,1,3 \rangle\\ = \langle 1+2t,2+t,-8+3t \rangle.$$
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