Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.2 Vectors in Three Dimensions - Exercises - Page 659: 32

Answer

(a) $4{\bf{i}} + 3{\bf{j}} - 2{\bf{k}} = \left( {4,3, - 2} \right)$ The length: $||4{\bf{i}} + 3{\bf{j}} - 2{\bf{k}}|| = \sqrt {29} $ (b) ${\bf{i}} + {\bf{j}} + {\bf{k}} = \left( {1,1,1} \right)$ The length: $||{\bf{i}} + {\bf{j}} + {\bf{k}}|| = \sqrt 3 $ (c) $4{\bf{j}} + 3{\bf{k}} = \left( {0,4,3} \right)$ The length: $||4{\bf{j}} + 3{\bf{k}}|| = 5$ (d) $12{\bf{i}} + 8{\bf{j}} - {\bf{k}} = \left( {12,8, - 1} \right)$ The length: $||12{\bf{i}} + 8{\bf{j}} - {\bf{k}}|| = \sqrt {209} $

Work Step by Step

We have ${\bf{i}} = \left( {1,0,0} \right)$, ${\bf{j}} = \left( {0,1,0} \right)$, ${\bf{k}} = \left( {0,0,1} \right)$. (a) The components of $4{\bf{i}} + 3{\bf{j}} - 2{\bf{k}}$: $4{\bf{i}} + 3{\bf{j}} - 2{\bf{k}} = 4\left( {1,0,0} \right) + 3\left( {0,1,0} \right) - 2\left( {0,0,1} \right) = \left( {4,3, - 2} \right)$ The length: $||4{\bf{i}} + 3{\bf{j}} - 2{\bf{k}}|| = \sqrt {{4^2} + {3^2} + {{\left( { - 2} \right)}^2}} = \sqrt {29} $ (b) The components of ${\bf{i}} + {\bf{j}} + {\bf{k}}$: ${\bf{i}} + {\bf{j}} + {\bf{k}} = 1\left( {1,0,0} \right) + 1\left( {0,1,0} \right) + 1\left( {0,0,1} \right) = \left( {1,1,1} \right)$ The length: $||{\bf{i}} + {\bf{j}} + {\bf{k}}|| = \sqrt {{1^2} + {1^2} + {1^2}} = \sqrt 3 $ (c) The components of $4{\bf{j}} + 3{\bf{k}}$: $4{\bf{j}} + 3{\bf{k}} = 0\left( {1,0,0} \right) + 4\left( {0,1,0} \right) + 3\left( {0,0,1} \right) = \left( {0,4,3} \right)$ The length: $||4{\bf{j}} + 3{\bf{k}}|| = \sqrt {{4^2} + {3^2}} = 5$ (d) The components of $12{\bf{i}} + 8{\bf{j}} - {\bf{k}}$: $12{\bf{i}} + 8{\bf{j}} - {\bf{k}} = 12\left( {1,0,0} \right) + 8\left( {0,1,0} \right) - 1\left( {0,0,1} \right) = \left( {12,8, - 1} \right)$ The length: $||12{\bf{i}} + 8{\bf{j}} - {\bf{k}}|| = \sqrt {{{12}^2} + {8^2} + {{\left( { - 1} \right)}^2}} = \sqrt {209} $
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