Chapter 13 - Vector Geometry - 13.2 Vectors in Three Dimensions - Exercises - Page 659: 16

The vectors $\overrightarrow{ AB}$ and $\overrightarrow{ PQ}$ are equivalent.

First, we have $$\overrightarrow{ AB}=B-A=(-4,2,3)-(0,0,0)=\langle -4,2,3 \rangle,$$ $$\overrightarrow{ PQ}=Q-P=(0,0,0)-(4,-2,-3)=\langle -4,2,3 \rangle.$$ Thus, the vectors $\overrightarrow{ AB}$ and $\overrightarrow{ PQ}$ are equivalent.