Chapter 13 - Vector Geometry - 13.2 Vectors in Three Dimensions - Exercises - Page 659: 15

The vectors $\overrightarrow{ AB}$ and $\overrightarrow{ PQ}$ are not equivalent.

First, we have $$\overrightarrow{ AB}=B-A=(-2,2,0)-(1,4,1)=\langle -3,-2,-1 \rangle,$$ $$\overrightarrow{ PQ}=Q-P=(-3,2,1)-(2,5,7)=\langle -5,-3,-6 \rangle.$$ So we see that the vectors $\overrightarrow{ AB}$ and $\overrightarrow{ PQ}$ are not equivalent.