Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 7 - Applications of Integration - 7.6 Exercises - Page 494: 1

Answer

$$\overline x = - \frac{4}{3}$$

Work Step by Step

$$\eqalign{ & {m_1} = 7,{\text{ }}{m_2} = 3,{\text{ }}{m_3} = 5 \cr & {\text{Located at }} \cr & {x_1} = - 5,{\text{ }}{x_2} = 0,{x_3} = 3 \cr & {\text{The moment about the origin is }} \cr & {M_0} = {m_1}{x_1} + {m_2}{x_2} + {m_3}{x_3} \cr & {M_0} = \left( 7 \right)\left( { - 5} \right) + \left( 3 \right)\left( 0 \right) + \left( 5 \right)\left( 3 \right) \cr & {M_0} = - 20 \cr & m{\text{ is the total mass of the system}} \cr & m = {m_1} + {m_2} + {m_3} \cr & m = 7 + 3 + 5 \cr & m = 15 \cr & {\text{The center of mass is }}\overline x = \frac{{{M_0}}}{m}{\text{, then}} \cr & \overline x = - \frac{{20}}{{15}} \cr & \overline x = - \frac{4}{3} \cr} $$
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