Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - Review Exercises - Page 313: 50

Answer

$2$

Work Step by Step

$\int ^{\frac {\pi }{4}}_{-\frac {\pi }{4}}sec^{2}tdt=\tan t]^{\pi /4}_{-\pi /4}=1-\left( -1\right) =2$
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