Answer
$\frac{231}{5}=46.2$
Work Step by Step
$\int ^{3}_{2}\left( x^{4}+4x-6\right) dx=\left( \dfrac {x^{5}}{5}+2x^{2}-6x\right) ]^3_{2}=\left( \dfrac {3^5}{5}+2\times 3^{2}-6\times 3\right) -\left( \dfrac {2^{5}}{5}+2\times 2^{2}-6\times 2\right) = \frac{231}{5}=46.2$
