Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - Review Exercises - Page 313: 42

Answer

$a)$ = $3$ $b)$ = $1$ $c)$ = $0$ $d)$ = $10$

Work Step by Step

$a)$ $\int_{{\,0}}^{{\,6}}$$f(x)$ $dx$ = $\int_{{\,0}}^{{\,3}}$$f(x)$ $dx$ + $\int_{{\,3}}^{{\,6}}$$f(x)$ $dx$ = $4$ - $1$ = $3$ $b)$ $\int_{{\,6}}^{{\,3}}$$f(x)$ $dx$ = -$\int_{{\,3}}^{{\,6}}$$f(x)$ $dx$ = -$(-1)$ = $1$ $c)$ $\int_{{\,4}}^{{\,4}}$$f(x)$ $dx$ = $0$ $d)$ $\int_{{\,3}}^{{\,6}}$$-10f(x)$ $dx$ = $(-10)(-1)$ = $10$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.