Answer
$a)$ = $3$
$b)$ = $1$
$c)$ = $0$
$d)$ = $10$
Work Step by Step
$a)$ $\int_{{\,0}}^{{\,6}}$$f(x)$ $dx$ = $\int_{{\,0}}^{{\,3}}$$f(x)$ $dx$ + $\int_{{\,3}}^{{\,6}}$$f(x)$ $dx$ = $4$ - $1$ = $3$
$b)$ $\int_{{\,6}}^{{\,3}}$$f(x)$ $dx$ = -$\int_{{\,3}}^{{\,6}}$$f(x)$ $dx$ = -$(-1)$ = $1$
$c)$ $\int_{{\,4}}^{{\,4}}$$f(x)$ $dx$ = $0$
$d)$ $\int_{{\,3}}^{{\,6}}$$-10f(x)$ $dx$ = $(-10)(-1)$ = $10$