Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - Review Exercises - Page 313: 41

Answer

$\textbf{(a)} \ 17$ $\textbf{(b)} \ 7$ $\textbf{(c)} \ 9$ $\textbf{(d)} \ 84$

Work Step by Step

$\textbf{(a)}$ $ {\displaystyle \int_{4}^{8}}[f_{(x)} + g_{(x)}]dx = {\displaystyle \int_{4}^{8}}f_{(x)}dx + {\displaystyle \int_{4}^{8}}g_{(x)}dx = 12 + 5 = 17$ $\\$ $\textbf{(b)}$ $ {\displaystyle \int_{4}^{8}}[f_{(x)} - g_{(x)}]dx = {\displaystyle \int_{4}^{8}}f_{(x)}dx - {\displaystyle \int_{4}^{8}}g_{(x)}dx = 12 - 5 = 7$ $\\$ $\textbf{(c)} {\displaystyle \int_{4}^{8}}[2f_{(x)} - 3g_{(x)}]dx = {\displaystyle \int_{4}^{8}}2f_{(x)}dx - {\displaystyle \int_{4}^{8}}3g_{(x)}dx = \\ \quad {\displaystyle 2\int_{4}^{8}}f_{(x)}dx - {\displaystyle 3\int_{4}^{8}}g_{(x)}dx = 2\times12 - 3\times5 = 24 - 15 = 9$ $\\$ $\textbf{(d)}$ ${\displaystyle \int_{4}^{8}}7f_{(x)}dx = {\displaystyle 7\int_{4}^{8}}f_{(x)}dx = 7\times12 = 84$
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