Answer
$= \frac{x^{2}}{2} - \frac{4}{x^{2}}+ c$
Work Step by Step
$\int (\frac{x^{4}+8}{x^{3}}) dx$
$\int (\frac{x^{4}}{x^{3}}+ \frac{8}{x^{3}}) dx$
$\int (x + \frac{8}{x^{3}}) dx$
$\int (x + 8x^{-3}) dx$
$= \frac{x^{2}}{2} + \frac{8x^{-2}}{-2}$
$= \frac{x^{2}}{2} + \frac{-2(-4x^{-2})}{-2(1)}$
$= \frac{x^{2}}{2} + -4x^{-2}$
$= \frac{x^{2}}{2} - \frac{4}{x^{2}}+ c$
