Answer
$f(x)=3x^2+x+7$
Work Step by Step
Integrate $f'(x)$:
$\int f'(x) dx=\int (9x^2+1)dx=3x^2+x+C$
$f(x)=3x^2+x+C$
Set in $f(0)=7$ and solve for $C$:
$7=3(0)^2+0+C$
$C=7$
$f(x)=3x^2+x+7$
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