Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.5 Exercises - Page 304: 97

Answer

$$\boxed{\textbf{See Work Step By Step}}$$

Work Step by Step

Let $$t=x/c$$ or $$x=ct$$ Therefore, $lower $ $limit = ca/c =a$ and $upper$ $limit = cb/c =b$ $$\int^{cb}_{ca}f(x)dx=\int^{b}_{a}f(ct)d(ct) = c\int^{b}_{a}f(ct)dt = c\int^{b}_{a}f(x)dx $$ We could do this last step because the variable of a definite integral is just a dummy variable
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