Answer
$$\boxed{\textbf{True}}$$
Work Step by Step
$$4\int sin(x)cos(x)dx=\int 2sin(x)cos(x)d(2x)=\int sin(2x)d(2x)$$
Let$$ t=2x$$
So, $$\int sin(2x)d(2x) =\int sin(t)dt = -cos(t)+C =-cos(2x)+C$$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.5 Exercises - Page 304: 95
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