Answer
$$\textbf{False}$$
Work Step by Step
$$\int (2x+1)^2dx =\frac{1}{2} \int (2x+1)^2d(2x+1)=\frac{1}{2}\frac{1}{3} (2x+1)^3=\frac{1}{6} (2x+1)^3$$ $$ \ne \frac{1}{3} (2x+1)^3$$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.5 Exercises - Page 304: 91
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