Answer
$$\textbf{False}$$
Work Step by Step
$$\int f(x)g(x) dx \ne \int f(x)dx \int g(x)dx $$
$$\int x(x^2+1)dx=\int x^3+xdx = \frac{x^4}{4}+\frac{x^2}{2}+C$$
$$\ne\frac{1}{2}x^2(\frac{1}{3}x^3+x)+C$$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.5 Exercises - Page 304: 92
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