Answer
Rolle's Theorem cannot be applied.
Work Step by Step
$f(x)$ is not continuous over the closed interval. $f(x)$ has a vertical asymptote at $x=\pi$ and another vertical asymptote at $x=2\pi$ and hence Rolle's Theorem cannot be applied.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 3 - Differentiation - 3.2 Exercises - Page 174: 22
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