Answer
$dy=.3$
$Δy=.331$
Work Step by Step
$y=x^{3}, x=1, Δx=dx=.1$
$y'=3x^{2}$
$dy=f'(x)\times dx= 3(1)^{2}\times .1=.3$
$Δy=f(x+Δx)-f(x)=f(1+.1)-f(1)=1.1^{3}-1^{3}=.331$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 3 - Applications of Differentiation - 3.9 Exercises - Page 236: 7
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