Answer
$\frac{-3}{(2x-1)^{2}}dx$
Work Step by Step
$y=\frac{x+1}{2x-1}$
Using quotient rule to find $\frac{dy}{dx}$, we have
$\frac{dy}{dx}= \frac{1(2x-1)-(x+1)2}{(2x-1)^{2}}= \frac{-3}{(2x-1)^{2}}$
Then, $dy= \frac{-3}{(2x-1)^{2}}dx$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 3 - Applications of Differentiation - 3.9 Exercises - Page 236: 15
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